- \n
- L\u00f4 c\u1eb7p l\u00e0 g\u00ec?<\/li>\n
- C\u00e1c lo\u1ea1i l\u00f4 c\u1eb7p v\u00e0 c\u00e1ch nu\u00f4i trong l\u00f4 \u0111\u1ec1<\/li>\n
- C\u00e1ch b\u1eaft b\u1ed9 l\u00f4 c\u1eb7p t\u1ef1 do<\/li>\n<\/ul>\n<\/div>\n
L\u00f4 c\u1eb7p l\u00e0 g\u00ec?<\/b><\/h2>\n
L\u00f4 c\u1eb7p l\u00e0 nh\u1eefng c\u1eb7p s\u1ed1 th\u01b0\u1eddng c\u00f3 c\u00f9ng \u0111\u1eb7c \u0111i\u1ec3m v\u1edbi nhau, ho\u1eb7c c\u00f3 khi ch\u1ec9 l\u00e0 m\u1ed9t s\u1ef1 k\u1ebft h\u1ee3p b\u1ea5t k\u1ef3 t\u1eeb 2 con s\u1ed1, d\u1ef1a theo ph\u00e1n \u0111o\u00e1n c\u1ee7a ng\u01b0\u1eddi ch\u01a1i. Nu\u00f4i l\u00f4 c\u1eb7p l\u00e0 ph\u01b0\u01a1ng ph\u00e1p ph\u1ed5 bi\u1ebfn trong b\u1ea1ch th\u1ee7 l\u00f4 \u0111\u1ec1 MB, MT v\u00e0 MN. N\u1ebfu b\u1ea1n ch\u01b0a bi\u1ebft \u0111\u1ebfn c\u00e1ch ch\u01a1i hay ho n\u00e0y th\u00ec h\u00e3y c\u00f9ng ch\u00fang t\u00f4i t\u00ecm hi\u1ec3u.<\/p>\n
C\u00e1c lo\u1ea1i l\u00f4 c\u1eb7p v\u00e0 c\u00e1ch nu\u00f4i trong l\u00f4 \u0111\u1ec1<\/b><\/h2>\n
- \n
- L\u00f4 c\u1eb7p \u0111\u1ed1i x\u1ee9ng: N\u1ebfu b\u1ea1n m\u1edbi b\u1eaft \u0111\u1ea7u ch\u01a1i l\u00f4 \u0111\u1ec1 v\u00e0 b\u1ea1n \u0111\u00e1nh trong ng\u00e0y th\u00ec n\u00ean ch\u1ecdn lo\u1ea1i l\u00f4 c\u1eb7p th\u01b0\u1eddng n\u00e0y \u0111\u1ec3 tr\u00e1nh nh\u1eefng tr\u01b0\u1eddng h\u1ee3p v\u1ec1 l\u1ed9n.<\/li>\n
- L\u00f4 \u0111\u1ec1 n\u00e0y c\u00f3 d\u1ea1ng 22-77, 33-88, 13-31,\u2026<\/li>\n
- B\u1ed9 l\u00f4 c\u1eb7p t\u1ef1 do l\u00e0 g\u00ec: L\u00e0 t\u1ed5 h\u1ee3p nh\u1eefng c\u1eb7p l\u00f4 t\u00f4 b\u1ea5t k\u1ef3 \u0111\u01b0\u1ee3c gh\u00e9p l\u1ea1i v\u1edbi nhau.<\/li>\n
- L\u00f4 n\u00e0y th\u01b0\u1eddng c\u00f3 d\u1ea1ng 45-12, 23-11, 13-54,\u2026<\/li>\n
- L\u00f4 c\u1eb7p tr\u00f9ng \u0111\u1ea7u: Lo\u1ea1i l\u00f4 n\u00e0y th\u01b0\u1eddng \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng cho ki\u1ec3u nu\u00f4i 2-3 ng\u00e0y c\u00f3 nh\u1eefng c\u1eb7p l\u00f4 \u0111\u1ea7u gi\u1ed1ng nhau.<\/li>\n
- L\u00f4 n\u00e0y c\u00f3 d\u1ea1ng 45-43, 24-27,13-19,\u2026<\/li>\n
- L\u00f4 c\u1eb7p tr\u00f9ng \u0111u\u00f4i: Lo\u1ea1i l\u00f4 n\u00e0y c\u00f3 \u0111\u1eb7c \u0111i\u1ec3m l\u00e0 nh\u1eefng c\u1eb7p l\u00f4 \u0111u\u00f4i gi\u1ed1ng nhau v\u00e0 r\u1ea5t hi\u1ec7u qu\u1ea3 d\u1ec5 sinh l\u1ee3i khi \u00e1p d\u1ee5ng cho ki\u1ec3u nu\u00f4i l\u00f4 2-3 ng\u00e0y.<\/li>\n<\/ul>\n
Ch\u00fang th\u01b0\u1eddng c\u00f3 d\u1ea1ng 56-76, 15-25, 33-53,\u2026<\/p>\n
C\u00e1ch b\u1eaft b\u1ed9 l\u00f4 c\u1eb7p t\u1ef1 do<\/b><\/h2>\n
<\/p>\n
- \n
- C\u00e1ch b\u1eaft b\u1ed9 l\u00f4 c\u1eb7p t\u1ef1 do<\/dd>\n<\/dl>\n
Trong \u0111\u00f3, nu\u00f4i l\u00f4 c\u1eb7p 3 ng\u00e0y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p ph\u1ed5 bi\u1ebfn nh\u1ea5t v\u00e0 c\u0169ng \u0111\u01b0\u1ee3c ki\u1ec3m ch\u1ee9ng l\u00e0 c\u00f3 t\u1ef7 l\u1ec7 th\u1eafng kh\u00e1 cao v\u00e0 \u1ed5n \u0111\u1ecbnh. V\u1eady, nu\u00f4i l\u00f4 c\u1eb7p 3 ng\u00e0y nh\u01b0 th\u1ebf n\u00e0o?<\/p>\n
- \n
- B\u01b0\u1edbc 1: Ch\u1ecdn m\u1ed9t c\u1eb7p s\u1ed1 b\u1ea5t k\u1ef3 m\u00e0 b\u1ea1n cho r\u1eb1ng t\u1ef7 l\u1ec7 ra trong 3 ng\u00e0y t\u1edbi cao nh\u1ea5t. V\u00ed d\u1ee5 b\u1ea1n ch\u1ecdn c\u1eb7p s\u1ed1 tr\u00f9ng \u0111u\u00f4i 47 \u2013 77<\/li>\n
- B\u01b0\u1edbc 2: V\u00e0o ti\u1ec1n 3 ng\u00e0y theo nguy\u00ean t\u1eafc: 1-3-10<\/li>\n<\/ul>\n
Ngh\u0129a l\u00e0 l\u1ea5y s\u1ed1 ti\u1ec1n b\u1ea1n v\u00e0o ng\u00e0y \u0111\u1ea7u ti\u00ean \u0111\u1ec3 l\u00e0m m\u1ed1c, \u0111\u1eb7t t\u1ef7 l\u1ec7 cho n\u00f3 l\u00e0 1. T\u1eeb \u0111\u00f3, b\u1ea1n nh\u00e2n 3 s\u1ed1 ti\u1ec1n l\u00ean v\u00e0 \u0111\u1eb7t \u1edf ng\u00e0y ch\u01a1i th\u1ee9 2. Ng\u00e0y th\u1ee9 3 b\u1ea1n nh\u00e2n 10 s\u1ed1 ti\u1ec1n ng\u00e0y \u0111\u1ea7u l\u00ean \u0111\u1ec3 \u0111\u1eb7t.<\/p>\n
V\u00ed d\u1ee5:<\/p>\n
- \n
- Ng\u00e0y 1 b\u1ea1n \u0111\u00e1nh 10 \u0111i\u1ec3m m\u1ed7i l\u00f4: 10 \u0111i\u1ec3m x 1 x 2 = 20 \u0111i\u1ec3m 1 c\u1eb7p. N\u1ebfu ng\u00e0y 1 ch\u01b0a v\u1ec1 con n\u00e0o \u0111\u00e1nh ti\u1ebfp ng\u00e0y 2.<\/li>\n
- Ng\u00e0y 2 b\u1ea1n \u0111\u00e1nh g\u1ea5p 3 l\u00ean: 30 \u0111i\u1ec3m x 1 x 2 = 60 \u0111i\u1ec3m 1 c\u1eb7p. N\u1ebfu ng\u00e0y 2 ch\u01b0a v\u1ec1 con n\u00e0o th\u00ec \u0111\u00e1nh ti\u1ebfp ng\u00e0y 3.<\/li>\n
- Ng\u00e0y 3 b\u1ea1n \u0111\u00e1nh g\u1ea5p 10 l\u1ea7n con s\u1ed1 ban \u0111\u1ea7u: 100 \u0111i\u1ec3m x 1 x 2 = 200 \u0111i\u1ec3m 1 c\u1eb7p (100 \u0111i\u1ec3m m\u1ed7i con).<\/li>\n<\/ul>\n
Sau 3 ng\u00e0y, n\u1ebfu c\u1eb7p l\u00f4 b\u1ea1n nu\u00f4i kh\u00f4ng ra nh\u01b0 ph\u00e1n \u0111o\u00e1n c\u1ee7a b\u1ea1n th\u00ec h\u00e3y d\u1eebng l\u1ea1i v\u00e0 t\u00ecm con l\u00f4 kh\u00e1c \u0111\u1ec3 nu\u00f4i ti\u1ebfp. Nh\u01b0 v\u1eady l\u00e0 b\u1ea1n bu\u1ed9c ph\u1ea3i b\u1ecf d\u1edf khung l\u00f4 \u0111ang theo v\u00e0 m\u1ea5t tr\u1eafng s\u1ed1 ti\u1ec1n \u0111\u00e3 ch\u01a1i. Tuy nhi\u00ean \u0111\u00f3 l\u00e0 c\u1ed9t m\u1ed1c quan tr\u1ecdng m\u00e0 b\u1ea1n c\u1ea7n ghi nh\u1edb. N\u1ebfu \u0103n, b\u1ea1n s\u1ebd \u0103n nhi\u1ec1u v\u00e0 l\u1ea5y l\u1ea1i \u0111\u01b0\u1ee3c s\u1ed1 v\u1ed1n \u0111\u00e3 b\u1ecf ra \u0111\u1ec3 nu\u00f4i trong nhi\u1ec1u ng\u00e0y. Nh\u01b0ng khi l\u00f4 kh\u00f4ng ra th\u00ec b\u1ea1n c\u0169ng c\u1ea7n b\u00ecnh t\u0129nh \u0111\u1ec3 t\u00ecm ra con l\u00f4 g\u1ee1 g\u1ea1c.<\/p>\n
L\u00f4 \u0111\u1ec1 v\u00e0 ch\u01a1i s\u1ed1 l\u00e0 lo\u1ea1i h\u00ecnh ch\u1ecbu \u1ea3nh h\u01b0\u1edfng c\u1ee7a r\u1ea5t nhi\u1ec1u y\u1ebfu t\u1ed1, trong \u0111\u00f3 c\u00f3 c\u1ea3 t\u00ednh to\u00e1n s\u1ed1 h\u1ecdc v\u00e0 may r\u1ee7i\u2026 V\u00ec v\u1eady s\u1ebd kh\u00f4ng c\u00f3 ph\u01b0\u01a1ng ph\u00e1p n\u00e0o \u0111\u00fang 100%. Nu\u00f4i l\u00f4 c\u1eb7p c\u0169ng v\u1eady. Tuy nhi\u00ean theo ki\u1ec3m ch\u1ee9ng th\u00ec ph\u01b0\u01a1ng ph\u00e1p n\u00f4i l\u00f4 c\u1eb7p n\u00e0y c\u00f3 kh\u1ea3 n\u0103ng tr\u00fang r\u1ea5t cao v\u00e0 \u0111\u1ed3ng th\u1eddi t\u0103ng bi\u00ean \u0111\u1ed9 l\u1ee3i nhu\u1eadn l\u00e2u d\u00e0i. N\u1ebfu b\u1ea1n x\u00e1c \u0111\u1ecbnh ch\u01a1i l\u00f4 \u0111\u1ec1 th\u01b0\u1eddng xuy\u00ean th\u00ec \u0111\u00e2y l\u00e0 m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p c\u1ea7n l\u01b0u t\u00e2m.<\/p>\n<\/article>\n<\/div>\n
\u0111\u00e1nh l\u00e0 tr\u00fang c\u1ea7u mi\u1ec1n b\u1eafc<\/h3>\n
- C\u00e1ch b\u1eaft b\u1ed9 l\u00f4 c\u1eb7p t\u1ef1 do<\/dd>\n<\/dl>\n
\n
N\u1ed9i dung<\/span>[Hi\u1ec3n th\u1ecb]<\/span><\/div>\n